Find the zeros of :
(i) 6 x2 -7x -3 (ii) 4x2 -4x +1
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☯ 6x² - 7x - 3 = 0
⇒ 6x² - 9x + 2x - 3 = 0
⇒ 3x(2x - 3) +1(2x- 3) = 0
⇒ (2x - 3)(3x + 1) = 0
⇒ x = 3/2 OR x = -1/3
☯ 4x² - 4x + 1
⇒ 4x² - 2x -2x +1
⇒ 2x(2x - 1) -1(2x - 1)
⇒ (2x - 1) ² = 0
⇒ x = 1/2
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