Question

Find the zeros of
of the
polynomial
P(x)=x²4​

Answer 1

Answer:

P ( x ) = x² - 4

We can also write this as :

⇒ P ( x ) = (x)² - (2)²

Identity : a² - b² = (a + b)(a - b)

⇒ P ( x ) = (x + 2)(x - 2)

To find the zeroes, P ( x ) = 0

•°• 0 = (x + 2)(x - 2)

Using Zero Product Rule

⇒ (x + 2) = 0 and (x - 2) = 0

⇒ x = - 2 and x = 2

Hence, the zeroes are 2 and - 2

Answer 2

Step-by-step explanation:

$x {}^{2} - 4 =(x + 2)(x - 2)$

$x = 2 \: or \: x = - 2$