Question

find the zeros of p(x)=2×2-x-6​

Answer 1

Answer:

Step-by-step explanation:

We find the zeroes by factorizing the equation x  

2

−x−6=0 as follows:

x  

2

−x−6=0

⇒x  

2

−3x+2x−6=0

⇒x(x−3)+2(x−3)=0

⇒(x+2)(x−3)=0

⇒x+2=0,x−3=0

⇒x=−2,x=3

Hence, the zeroes of the polynomial x  

2

−x−6=0 are 3,−2.

Answer 2

$i) \: \: \: p(0) = 2 (0) {}^{2} - 0 - 6 \\ \\ = 6 \\ \\ ii) \: \: p(1) = 2(1) {}^{2} - 1 - 6 \\ = 2 - 1 - 6 \\ - 5 \\ \\iii) p(2) = 2(2) {}^{2} - 2 - 6 \\ = 8 - 2 - 6 \\ = 0$