Math, asked by podarashleshnt123, 6 months ago

find the zeros of P(x) = х2-68​

Answers

Answered by Anonymous
2

Answer:

-68

Step-by-step explanation:

p(0)=0×2-68

p(0)=0-68

p (0)=-68

Answered by llxdevilgirlxll
11

\huge\bigstar\huge\tt\underline\red{Answer}\bigstar

p(x) \:  =  \: x ^{2}  - 68

p(0) \:  =  \: 0 \times 2 \:  - 68

p(0) \:  = 0 - 68

p(0) \:  =  - 68

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