CBSE BOARD X, asked by Ridhima2248, 1 year ago

Find the zeros of p(x)= 2x^2 - 50

Answers

Answered by HappiestWriter012
3

Answer : 5, - 5 are the zeroes of the polynomial

Step by step explanation :

To find the zeroes of polynomial, We need find values of x for which the polynomial would become zero.

If a is the zero of the polynomial f(x), then f(a) = 0.

Given Polynomial p(x) = 2x^2 - 50

Its a polynomial of degree 2. So, It has utmost 2 zeroes. We can find by factoring it.

Let the zero of polynomial p(x) is a.

So,

  • p(a) = 0
  • 2(a)^2 - 50 = 0
  • 2 [ a² - 25] = 0
  • a² = 25
  • a = √25
  • a = ± 5

Therefore, Zeroes of the polynomial p(x) are 5, - 5.

Answered by prikishan28
0

Answer:

hte is my answer

Explanation:

Answer : 5, - 5 are the zeroes of the polynomial

Step by step explanation :

To find the zeroes of polynomial, We need find values of x for which the polynomial would become zero.

If a is the zero of the polynomial f(x), then f(a) = 0.

Given Polynomial p(x) = 2x^2 - 50

Its a polynomial of degree 2. So, It has utmost 2 zeroes. We can find by factoring it.

Let the zero of polynomial p(x) is a.

So,

p(a) = 0

2(a)^2 - 50 = 0

2 [ a² - 25] = 0

a² = 25

a = √25

a = ± 5

Therefore, Zeroes of the polynomial p(x) are 5, - 5.

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