Find the zeros of p (x)3x square + 5 x minus 2
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what is this not understood
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Hey
Here is your answer,
3x^2 + 5x - 2 =0
3x^2 + 6x - x - 2 = 0
3x ( x + 2) - 1 ( x + 2) =0
( X + 2) ( 3x - 1) =0
X + 2 =0
X =-2
3x -1=0
X = 1/3
Hope it helps you!
Here is your answer,
3x^2 + 5x - 2 =0
3x^2 + 6x - x - 2 = 0
3x ( x + 2) - 1 ( x + 2) =0
( X + 2) ( 3x - 1) =0
X + 2 =0
X =-2
3x -1=0
X = 1/3
Hope it helps you!
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