Question

find the zeros of p(x)=4x^2-5

Answer 1

Answer:

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Answer 2

Answer :-

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$p(x) = 4 {x}^{2} - 5 \\ 0 = 4 {x}^{2} - 5 \\ 4 {x}^{2} = 5 \\ {x}^{2} = \frac{5}{4} \\ x = \sqrt{ \frac{5}{4} }$

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zero of the polynomial is

$= (x - \sqrt{ \frac{5}{4} } )$

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HOPE THIS HELPS YOU!!!!!!!!!