Math, asked by nishitha3, 6 months ago

find the zeros of P(x)=6x²-x-2

Answers

Answered by gitanjali4922

9

Step-by-step explanation:

P(x)=6x²-x-2

= 6x2-4x+3x -2

= 2x (3x-2) + 1 (3x-2)

= (3x-2)(2x +1)

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