Math, asked by priyanshukumar94101, 1 month ago

find the zeros of p(x)=(x-1)(x-2)(x+3)​

Answers

Answered by pranayteja7
1

Answer:

1,2,(-3)

Step-by-step explanation:

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Answered by IIBrainlyArpitII
0

Answer:

Here is u r answer

Zeros of p(x)=(x-1)(x-2)(x+3)​ ARE -

(x-1)=0

x=1

(x-2)=0

x=2

(x+3)=0

x=-3

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