Math, asked by mkqwert7289, 1 year ago

Find the zeros of p(x)=(x-4)whole square -(x-6)whole square

Answers

Answered by prakharverma2209
2

Answer:

4

Step-by-step explanation:

p(x) = (x - 4)^2 - (x - 6)^2

= x^2 + 16 - 8x - ( x^2 + 36 - 12x)

= x^2 + 16 - 8x - x^2 - 36 + 12x

= - 16 + 4x

= 4x - 16

= 4(x - 4)

p(x) = 4(x - 4)

the polynomial x is zero when

4(x - 4) = 0

x - 4 = 0/4

x - 4 = 0

x = 4

The zero of this polynomial is 4

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Answered by Varun20102
2

Answer : 5

For Step by Step Explaination please refer to the picture.

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