Find the zeros of p(x)=(x-4)whole square -(x-6)whole square
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Answered by
2
Answer:
4
Step-by-step explanation:
p(x) = (x - 4)^2 - (x - 6)^2
= x^2 + 16 - 8x - ( x^2 + 36 - 12x)
= x^2 + 16 - 8x - x^2 - 36 + 12x
= - 16 + 4x
= 4x - 16
= 4(x - 4)
p(x) = 4(x - 4)
the polynomial x is zero when
4(x - 4) = 0
x - 4 = 0/4
x - 4 = 0
x = 4
The zero of this polynomial is 4
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Answered by
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Answer : 5
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