Question

Find the zeros of P( X) = x square+ 2 root 2 - 6

Answer 1

I HOPE YOU HAVE GOT YOUR ANSWER ..........
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Answer 2

p(x)= x square - root 2x + 3 root2x - 6
= x ( x - root 2) + 3root 2 (x - root2)

$(x + 3 \sqrt{2})(x - \sqrt{2)}$
$x = - 3 \sqrt{2}$

or
$x = \sqrt{2}$