Question

Find the zeros of p(x)=x square minus root2x minus 12

Answer 1

${x}^{2} - \sqrt{2} x - 12 \\ {x}^{2} - 3\sqrt{2} x + 2 \sqrt{2} x - 12 = 0 \\ x(x - 3 \sqrt{2} ) + 2 \sqrt{2} (x - 3 \sqrt{2} ) \\ (x - 3 \sqrt{2} )(x + 2\sqrt{2} ) = 0 \\ x = 3 \sqrt{2} and - 2 \sqrt{2}$