Question

Find the Zeros of p(x)=x²-3x

Answer 1

Hi Friend !!!

Here is ur answer !!!

x²-3x = 0

x(x-3) = 0

x = 0. x-3 = 0

x = 0 , x = 3

Hope it helps u :-)

Answer 2

Given:      $p(x)= x^{2} - 3x$

we can find zeros of any equation by putting the equation equals to zero,

    $x^{2} -3x=0\\x(x-3)=0\\x=0 or x= 3$

So the answer will be either x = 0 or x = 3

#SPJ2