Question

find the zeros of polnomial 3x²-11x+8​

Answer 1

3x²-11x+8

3x²-3x-8x+8

3x(x-1) -8(x-1)

(3x-8)(x-1)

3x-8=0 , x-1=0

3x=8 , x= 1

x=8/3 , x=1

so the zeroes of the polynomial is 8/3 & 1

Answer 2

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Q1) Find the zeros of polynomial 3x²-11x+8=0

$\: \underline{\boxed { \bf \color{orange} \: solution}}$

$\: \dashrightarrow \bf{3 {x}^{2} - 11x + 8 = 0 }$

$\: \dashrightarrow \bf{3 {x}^{2} - 3x - 8x - 8 = 0}$

$\ \dashrightarrow \bf{3 x(x - 1) - 8(x - 1) = 0}$

$\: \: \dashrightarrow \bf{x = 1 \: and \: x = \frac{ 8}{3} are \: the \: solutions \: }$