Question

Find the zeros of polynomial.
1) 3x²–5x–2.
2) 6x²–5x–4.
3) x²–22x+40.
4) x²–11x–80.
5) x²–3x–40.​

Answer 1

$\sf\huge\bold{\underline{\underline{{Solution}}}}$

1) 3x²-5x-2

3×2= 6 and -3×-2= 6

➙3x²-3x-2x-2

Taking out 3x & 2 common

➙3x(x-1)+2(x-1)

➙(3x+2)(x-1)=0

➙3x+2=0 & x-1=0

x= -2/3 & 1

2) 6x²-5x-4

6×-4= -24 and -8×3= -24

➙6x²-8x+3x-4

Taking out 2x & 1 common

➙2x(3x-4)+1(3x-4)

➙(2x+1)(3x+4)=0

➙2x+1=0 & 3x+4=0

x= -1/2 & -4/3

3) x²-22x+40

40×1= 40 & -20× -2= 40

➙x²-20x-2x+40

Taking out x & 2 common

➙x(x-20)-2(x-20)

➙(x-2)(x-20)=0

➙x-2=0 & x-20=0

x= 2 & x=20

4) x²-11x-80

80= 16 × 5

-11 = -16+5

➙x²-11x-80

➙x²-16x+5x-80

Taking out x and 5 common

➙x(x-16)+5(x-16)

➙(x+5)(x-16)=0

➙x+5=0 & x-16=0

x= -5 & x= 16

5)x²-3x-40

40×1=40

40= 8×5

-3= -8+5

➙ x²-3x-40

➙x²-8x+5x-40

Taking out x and 5 common

➙x(x-8)+5(x-8)

➙(x+5)(x-8)

➙(x+5)(x-8)=0

➙x+5=0 & x-8=0

x= -5 & x= 8

_____________________________________

How to factorise?

2x²+7x+3

The coefficient of x² is 2

7x is a middle term and its coefficient is 7.

and the constant" is +3

Step-1 : Multiply the coefficient of x² by the constant 3×2= 6

Step-2 : Find two factors of 6 whose sum is equal to the coefficient of the middle term, which is 7.

⍐ follow this steps above in all quadratic equation.

Answer 2

Answer:

abb beda tej ho raha ho

but yes I need urs