Find the zeros of polynomial 3x^2+49x-16
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Let the given polynomial be
p(x) = 3x²+49x-16
To Find :
It's Zeroes.
Solution :
As it is a quadratic polynomial so it has 2 zeroes.
3x²+49x-16 = 0
Well the statement is wrong ,
The statement can be :
3x²+49x+16 = 0
3x²+48x+x+16 = 0
3x(x+16)+1(x+16) = 0
(x+16)(3x+1) = 0
Here x = -16 and x = -⅓
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