Question

find the zeros of polynomial 3x^2 + 4x- 4 and verify its relationship with coefficients​

Answer 1

Answer:

Step-by-step explanation:

Answer 2

Hęřę įš ùř ąńšwęř....♥♡♥

=)

$3x {}^{2} + 4x - 4$

$= > 3x {}^{2} + 6x - 2x - 4$

$= > 3x(x + 2) - 2(x + 2)$

$= > (3x - 2)(x + 2)$

$= > x = \frac{2}{3} or \: x = - 2$

Verification:--

$= > \alpha + \beta = \frac{ - b}{a}$

$= > \frac{2}{3} - 2 = \frac{ - 4}{3}$

$= > \frac{2 - 6}{3} = \frac{ - 4}{3}$

$= > \frac{ - 4}{3} = \frac{ - 4}{3}$

Now,

$\alpha . \beta = \frac{c}{a}$

$= > \frac{2}{3} .( - 2) = \frac{ - 4}{3}$

$= > \frac{ - 4}{3} = \frac{ - 4}{3}$

Hence,relationship of zeroes with its coefficient is verified.

Høpé iť héłpś...♡♡