Question

find the zeros of polynomial ✓3x²+10x+7✓3 and verify the relationship between the zeros and coefficient

Answer 1

There is your answer

Answer 2

Hii Friend,

P(X) = ✓3X²+10X+7✓3

=> ✓3X²+7X+3X+7✓3

=> X(✓3X+7) +✓3(✓3X+7)

=> (✓3X+7) (X+✓3)

=> (✓3X+7) = 0 Or (X+✓3) = 0

=> X = -7/✓3 OR X = -✓3.

Let Alpha = -7/✓3 and beta = -✓3

Relationship between the zerso and the coefficient.

Sum of zeros = Alpha + Beta = -7/✓3 + (-✓3) = -7/✓3 -✓3 = -7-3/✓3 = -10/✓3 = -(Coefficient of X/Coefficient of X².


Product of zeros = (Alpha × Beta) = (-7/✓3 × -✓3) = 7✓3/✓3 = Constant term/Coefficient of X².



HOPE IT WILL HELP YOU..... :-)