Question

Find the zeros of polynomial 3xsq+x-2

Answer 1

Answer:

Step-by-step explanation:

f(x) = 3x² + x - 2

f( - 1 ) = 3( - 1)² - 1 - 2 = 0

( 3x² + x - 2 ) ÷ ( x + 1 ) = 3x - 2 ⇒ x = $\frac{2}{3}$

The zeros of given polynomial are ( - 1 ) and ( $\frac{2}{3}$ )