Question

find the zeros of polynomial 4t2-20​

Answer 1

Answer:

√5/2 and -√5/2

To find zeroes, the polynomial should equate to 0

4t²-5=0

4t²=5

t²=5/4

t=t√5/2

Answer 2

Answer:

Let f(u)=4u2+8u

To calculate the zeros of the given equation, put f(u)=0.

4u2+8u=0

4u(u+2)=0

u=0,u=−2

The zeros of the given equation is 0 and −2.

Sum of the zeros is 0+(−2)=−2.

Product of the zeros is 0×−2=0.

According to the given equation,

The sum of the zeros is,

a−b=4−(8)

=−2

The product of the zeros is,

ac=40

=0

Hence, it is verified that,

sum of zeros = coefficient of x² − coefficient of x

And,

product of zeros = coefficient of x² constant term