Question

find the zeros of polynomial 4u ^ 2 + 8u and verify the relationship between zeros and cofficients

Please guys help me it's very urgent​

Answer 1

let p(X) = 4u² +8u

=4 u(u+2)

now, p(X) = 0

=> 4u( u+2) =0

=> 4u =0 or u+2 =0

=> u =0/4 or u =-2

=> u =0 or u =-2

so, zeros are 0&-2

by the polynomial , a =4 , b= 8 , c= 0

sum of zeros = 0+(-2)=-2 = (-2/1)×4/4= -8/4 -b\a

product of zeros=0×-2 = 0 =0/1 = 0/1 × 4/4 = 0/4 = c/a

Verified