Question

find the zeros of polynomial 5xsquare+7y
pleasz fast solve please​

Answer 1

given expression :

$5 {x}^{2} + 7y$

now

${(5x)}^{2} + {(\sqrt{7})}^{2} \\ = \\ {(5x + \sqrt{7} )}^{2} - 10x \sqrt{7}$

therefore these are the factors

however I think your question should be 5x^2-7y

if that is the q then

$5 {x}^{2} - 7y \\ = \\ {(5x)}^{2} - {( \sqrt{7}) }^{2} \\ = \\ (5x + \sqrt{7} )(5x - \sqrt{7} ) \\ = \\ so \: \: therefore \\ \alpha = \frac{ \sqrt{7} }{5} \\ and \: \\ \beta = \frac{ - \sqrt{7} }{5}$