Question

Find the zeros of polynomial 6x^2-3-7x and verify the relationship between the zeroes and the coefficients.

Answer 1

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Answer 2

$\textbf{\underline{\underline{According\:to\:the\:Question}}}$

6x² - 3 - 7x

= 6x² - 9x + 2x - 3

= 3x(2x - 3) + 1(2x - 3)

= (3x + 1)(2x - 3)

(3x + 1) = 0

3x = -1

${\boxed{\sf\:{x=-\dfrac{1}{3}}}}$

(2x - 3) = 0

2x = 3

${\boxed{\sf\:{x=\dfrac{3}{2}}}}$

Hence,

★Sum of zeroes :-

${\boxed{\sf\:{-\dfrac{1}{3}+\dfrac{3}{2}}}}$

${\boxed{\sf\:{n=\dfrac{7}{6}}}}$

★Product of zeroes :-

${\boxed{\sf\:{-\dfrac{1}{3}\times\dfrac{3}{2}}}}$

${\boxed{\sf\:{-\dfrac{1}{2}}}}$