Question

Find the zeros of polynomial 6x square + 7 x + 2

Answer 1

Step-by-step explanation:

$\bf\red{ \mapsto: {6x}^{2} + 7x + 2 = 0} \\ \\ \bf\orange{ \mapsto: {6x}^{2} + (4x + 3x) + 2 = 0} \\ \\ \bf\green{ \mapsto: {6x}^{2} + 4x + 3x + 2 = 0} \\ \\ \bf\blue{ \mapsto:2x(3x + 2) + 1(3x + 2) = 0 } \\ \\ \bf\pink{ \mapsto:(3x + 2)(2x + 1) = 0 } \\ \\ \bf\red{ \underline{ \boxed{ \bigstar: 3x + 2 = 0 \: \: \: x = \frac{ - 3}{2} \: \bigstar}}} \\ \\ \bf\red{ \underline{ \boxed{ \bigstar: 2x + 1 = 0 \: \: \: x = \frac{ - 1}{2} \: \bigstar}}} \\ \\ \\ \huge{ \blue{ \ddot{ \smile }}}$

Answer 2

Answer:

Solution:6x²+7x+2

6x²–(4+3)x+2=0

6x²–4x–3x +2=0

6x(x–6) – 1(x+6)=0

therefore,(x–6) (x+6)

either,x–6=0

x=6

or

x+6=0

x= –6