Question

find the zeros of polynomial 6x2+7x-3?​

Answer 1

Answer:

$= > 6 {x}^{2} + 7x - 3 = 0 \\ = > 6 {x}^{2} + 9x - 2x - 3 = 0 \\ = > 3x(2x + 3) - 1(2x + 3) = 0 \\ = > (3x - 1)(2x + 3) = 0 \\ = > either \: 3x - 1 = 0 \: or \: 2x + 3 = 0 \\ = > either \: x = \frac{1}{3} \: or \: x = - \frac{3}{2} .$

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Answer 2

Answer:

=6x²+9x-2x-3=3x(2x+3)-1(2x+3)=(3x-1)(2x+3).

so 2x+3=0, x=-3/2

or 3x-1=0, x=1/3

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