Question

find the zeros of polynomial 7x²-15x+2

Answer 1

7x2 - 15x +2 =0
7x2 - 14x - x + 2=0
7x(x-2) -1(x-2)=0
(7x-1) (x-2)=0
7x-1=0
x=1/7
x-2=0
x=2
so, all the zeroes are 1/7 and 2.


HOPE IT HELPS!

Answer 2

Given equation  : 7x^2 - 15x + 2

Firstly, split 15 in two numbers such that their product become equal to the product of 2 and the co efficient of x^2.

We can write 15 as ( 14 + 1 ), as the product of 14 and 1 is equal to the product of 2 and 7 .

∴ 15 = 14 + 1

Now,

⇒ 7x^2 - ( 14 + 1 )x + 2

⇒ 7x^2 - 14x - x + 2

⇒ 7x( x - 2 ) - ( x - 2 )

⇒ ( x - 2 )( 7x - 1 )

Therefore, ( x - 2 ) are the factors of the given equal. But if we want the zeroes, equation must be equal to 0.

So, ( x - 2 )( 7x - 1 ) = 0

       By Zero product rule

x - 2 = 0    or  7x - 1 = 0

x - 2 + 2 = 2    or   7x - 1 + 1 = 1

x = 2     or   7x = 1

x = 2    or    x = 1 / 7

Thus, 2 and 1 / 7  are the zeroes of the given polynomial.

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