Question

find the zeros of polynomial 9 ✖ 2-6 ✖ +1​

Answer 1

Your QUESTION :---

$9 {x}^{2} - 6x + 1$

Your SOLUTION of your answer is

$9 {x}^{2} - 6x + 1 = 0$

$9 {x}^{2} - 3x - 3x + 1 = 0$

$3x(3x - 1) - 1(3x - 1) = 0$

$(3x - 1)(3x - 1) = 0$

Here value for X is only and only = (3x-1)

that is ----

$x = \frac{1}{3}$

Answer 2

Answer:

X=1/3;1/3 it has two same value