Question

Find the zeros of polynomial 9t²-6t+1and verify the relationship between the
zeros and co-efficients

Answer 1

Here is your answer


hope it help you

Answer 2

9t² - 6t + 1 = 0

⇒ 9t² - 3t - 3t + 1 = 0

⇒ 3t(3t-1) -1(3t-1) = 0

⇒ (3t-1)(3t-1)=0

⇒ (3t-1)² = 0

So both roots are same

⇒ 3t = 1

⇒ t = 1/3

Verification of relationships:

Sum of roots = (1/3)+(1/3) = 2/3 = -(-6)/9 = -b/a

Product of roots = (1/3)*(1/3) = 1/9 = c/a