find the zeros of polynomial f(x)=x³-2x²-7x+14, if it is given that the sum of its 2 zeroes is 0.
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sum of zeroes =a+b
so by hit and trial method find one root as
putting x=1
1-2-7+14=6
it does not satisfy so,
putting x=2
8-8-14+14=0 so one root is (x-2)
divide your equation by (x-2)
result will br a equation as x(square)-14
do one is root 7 and second is -root 7
so by hit and trial method find one root as
putting x=1
1-2-7+14=6
it does not satisfy so,
putting x=2
8-8-14+14=0 so one root is (x-2)
divide your equation by (x-2)
result will br a equation as x(square)-14
do one is root 7 and second is -root 7
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