Question

find the zeros of polynomial have x2-60x+800​

Answer 1

Answer:

make factor of 800 I think 2*2*2*2*2*5*5 ,now take x2 +40x+20x+800 x(x+40)+20(x+40) =0

x+40=0

x=-40

x+20=0

x=-20

Answer 2

Answer:X

Step-by-step explanation:

Factoring x2-60x+800

The first term is, x2 its coefficient is 1 .

The middle term is, -60x its coefficient is -60 .

The last term, "the constant", is +800

Step-1 : Multiply the coefficient of the first term by the constant 1 • 800 = 800

Step-2 : Find two factors of 800 whose sum equals the coefficient of the middle term, which is -60 .

-800 + -1 = -801

-400 + -2 = -402

-200 + -4 = -204

-160 + -5 = -165

-100 + -8 = -108

-80 + -10 = -90

-50 + -16 = -66

-40 + -20 = -60 That's it

Step-3 : Rewrite the polynomial splitting the middle term using the two factors found in step 2 above, -40 and -20

x2 - 40x - 20x - 800

Step-4 : Add up the first 2 terms, pulling out like factors :

x • (x-40)

Add up the last 2 terms, pulling out common factors :

20 • (x-40)

Step-5 : Add up the four terms of step 4 :

(x-20) • (x-40)