find the zeros of polynomial if two of its zeri are (2+√3) and(2-✓3)
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Answer:
Step-by-step explanation:
the α = 2+√3
and β = 2-√3
now the general form of quadratic equation is
x² - (α + β ) x + (αβ)
x² - (2+√3 + 2-√3)x + (2+√3)(2-√3)
x²- 4x + 1
now
zeros = -b ±√b²-4ac /2a
= -(-4) ± √(4)² - 4 / 2
= 4 ± √16-4 /2
= 4±√12 /2
= 4±2√3/2
= 2 +√3 and 2-√3
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