Question

find the zeros of polynomial in 9u^2-16=0​

Answer 1

Answer:

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#Here's ur answer...☆☆☆

Step-by-step explanation:

$\boxed{ \huge{ \mathcal{ \bigstar{ \pink{answer....}}}}}$

$\bold{ \green{given...f(u) = 9 {u}^{2} - 16 }}\\ = (3u) {}^{2} - (4) {}^{2} \\ by \: using \: ({x}^{2} - {y}^{2}) = (x + y)(x - y) \\ = (3u + 4)(3u - 4) \\ \bold{ \red{zeroes \: of \: f(u) = \frac{ - 4}{3} or \: \frac{4}{3} }}( \blue{answer...})$

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