find the zeros of polynomial of x^+2x+1
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Step-by-step explanation:
x^2 + 2x + 1 = 0
=> x^2 + 1x + 1x + 1 = 0
=> x( x+1 ) + 1( x+1 ) = 0
=> ( x+1 ) ( x+1 ) = 0
therefore ;
x = -1 .....!!!!!!
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