find the zeros of polynomial P of x is equal to x square - 2 x minus 8
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p(x)=x²-2x-8
p(x)=x²-4x+2x-8
p(x)=x(x-4)+2(x-4)
=>(x+2)(x-4)
Hence, the zeroes of the polynomial are 4, -2.
CuteMunda112:
hlw hannah
Answered by
1
Answer:
Step-by-step explanation:
X2 - 2x - 8
X2 - 4x + 2x -8
x ( x - 4)+ 2( x -4)
(X+2) (X- 4)
X=-2. Or X= 4
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