Math, asked by shryanshverma7733, 2 days ago

Find the zeros of polynomial
P (x) = 6 + 5 x-x^2

Answers

Answered by keybytegamer1m
2

Answer:

p(x) = (x - 6)(x - 5)

Substitute the value of p(x) as 0, as we don't have value of x as given

⇒ 0 = (x - 6)(x - 5)

Switch the sides

⇒ (x - 6)(x - 5) = 0

Split into possible cases

⇒ x - 6 = 0

x - 5 = 0

Solve the equations

⇒ x = 6

x = 5

The final solutions are :

⇒ \text{x}_{1}x

1

= 5

\text{x}_{2}x

2

= 6

∴ The zeroes of the polynomial p(x) = (x - 6)(x - 5) are \text{x}_{1}x

1

= 5 and \text{x}_{2}x

2

= 6

Answered by aravind077
0

Answer:

answer is 6

Step-by-step explanation:

their is no time to explain so, I said direct answer

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