Find the zeros of polynomial
P (x) = 6 + 5 x-x^2
Answers
Answered by
2
Answer:
p(x) = (x - 6)(x - 5)
Substitute the value of p(x) as 0, as we don't have value of x as given
⇒ 0 = (x - 6)(x - 5)
Switch the sides
⇒ (x - 6)(x - 5) = 0
Split into possible cases
⇒ x - 6 = 0
x - 5 = 0
Solve the equations
⇒ x = 6
x = 5
The final solutions are :
⇒ \text{x}_{1}x
1
= 5
\text{x}_{2}x
2
= 6
∴ The zeroes of the polynomial p(x) = (x - 6)(x - 5) are \text{x}_{1}x
1
= 5 and \text{x}_{2}x
2
= 6
Answered by
0
Answer:
answer is 6
Step-by-step explanation:
their is no time to explain so, I said direct answer
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