Find the zeros of polynomial P(x)=6x^3+23x^2-5x-4
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Given polynomial,
↪ p(x) = 6x³ + 23x² - 5x - 4
Let,
- a = 6
- b = 23
- c = - 5
- d = - 4.
➡ α + ß + γ = -b/a = - 23/6
➡ αß + ßγ + αγ = c/a = -5/6
➡ αßγ = -d/a = -(-4)/6 = 4/6 = 2/3
Hence, it is solved...
Step-by-step explanation:
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