Math, asked by narasimhappa1989, 1 year ago

Find the zeros of polynomial P(x)=6x^3+23x^2-5x-4​

Answers

Answered by Anonymous
2

Given polynomial,

p(x) = 6x³ + 23x² - 5x - 4

Let,

  • a = 6
  • b = 23
  • c = - 5
  • d = - 4.

α + ß + γ = -b/a = - 23/6

αß + ßγ + αγ = c/a = -5/6

αßγ = -d/a = -(-4)/6 = 4/6 = 2/3

Hence, it is solved...

Step-by-step explanation:

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