Question

Find the zeros of polynomial P(x) = 6x2 +5x-1​

Answer 1

Step-by-step explanation:

6x²+5x-1

split the middle term

6x²×-1 = -6x² = 6x and -x

( 6x *-x = -6x² and 6x-x = 5x)

6x²+6x-x-1

6x(x+1) -1(x+1)

(6x-1) ( x+1)

1) put 6x-1= 0

6x=1

x=1/6

2) put x+1=0

x=-1

that means zeroes are 1/6 and -1 .

Answer 2

Answer:

P(x) = 6x² + 5x - 1

= 6x² - 1x + 6x -1

= x (6x - 1) + 1 (6x - 1)

= (x+1) (6x - 1)

x = -1 , 1/6

So the the zeros of polynomial P(x) = 6x² + 5x - 1

are -1 , 1/6

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