Question

find the zeros of polynomial p(x)=a(x^2+1)-x(a^2+ 1) ​

Answer 1

Answer:

1/a and a

Step-by-step explanation:

Answer 2

Answer:

-1/a and a

Step-by-step explanation:

a(x2+1)-x(a2+1)

ax(x-a)+(x-a)

(ax+1)(x-a)

x=-1/a,a.