Find the zeros of polynomial p(x)=x³-3
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Answer:
Given P(x)=x
3
−x
To find the zeros of P(x), let P(x)=0
⟹x
3
−x=0
⟹x(x
2
−1)=0
⟹x(x−1)(x+1)=0
⟹x=0 and x−1=0 and x+1=0
⟹x=0,1,−1 are the zeros of P(x)
Thus, the number of zeros of P(x) is 3.
Hence, the answer is 3.
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