Find the zeros of polynomial p(x)=x³- 3x²- 25x +75, if its two zeros are equal in magnitude but opposite in sign
anjalismenon23p4v4hh:
It's a cubic polynomial, so wouldn't it have 3 zeroes?
yup
the question only mentions 2 zeroes, so you wouldnt be able to apply the formula properly
oh! i did it.
how?
wait a min
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Answered by
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P(x) = x^3 - 3x^2-25x+75
Alpha+beeta+gama = -(-3)\1
Alpha + (-alpha) + beeta =3
Beeta =3
Alpha into (-alpha) into beeta = -75
-alpha^2 into 3 = -75
Alpha^2 = 75/3 = 25
Alpha = 5
Alpha+beeta+gama = -(-3)\1
Alpha + (-alpha) + beeta =3
Beeta =3
Alpha into (-alpha) into beeta = -75
-alpha^2 into 3 = -75
Alpha^2 = 75/3 = 25
Alpha = 5
Hipe it helps!!
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