Question

Find the zeros of polynomial p(y)=2y²+3root5y-10

Answer 1

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Hey Mate!!

p(y) = 2y² + 3√5y - 10

→ 2y² + 4√5y - √5y - 10

→ 2y(y + 2√5) - √5(y + 2√5)

→ (2y - √5)(y + 2√5)

⇒ (2y - √5) and (y + 2√5) are factors of p(y).

→ 2y - √5 = 0

→ y = √5/2

→ y + 2√5 = 0

→ y = -2√5

Therefore, √5/2 and -2√5 are zeroes of p(y).