Question

Find the zeros of polynomial p(y)=(y-3)^2 -(y+3)^2

Answer 1

Answer:

Let a= y-3

b=y+3

a^2-b^2=(a+b)(a-b)

(y-3+y+3)(y-3-y-3)=0

2y*-6 = 0

2y = 6

y = 3