Question

Find the zeros of polynomial (x-2)^2 -(X+2)^2
${(x - 2)}^{2} - {(x + 2)}^{2}$
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Answer 1

${(x - 2)}^{2} - {(x + 2)}^{2}$

$= > (x - 2 + x + 2)(x - 2 - x - 2)$

$= > 2x( - 4)$

$= > -8x$

For this to be zero, x = 0

Hence zero of the polynomial = 0

Answer 2

Answer:

{(x - 2)}^{2} - {(x + 2)}^{2}(x−2)

2

−(x+2)

2

= > (x - 2 + x + 2)(x - 2 - x - 2)=>(x−2+x+2)(x−2−x−2)

= > 2x( - 4)=>2x(−4)

= > -8x=>−8x

For this to be zero, x = 0

Hence zero of the polynomial = 0