Math, asked by nishashah34, 5 hours ago

find the zeros of polynomial x^2+7x+10 and the verify relation between the zeros and cooficient​

Answers

Answered by singhalvarun2004
1

Step-by-step explanation:

x ^{2}  + 7x + 10 \\  x ^{2}  + 5x + 2x + 10 \\ x(x + 5) + 2(x + 5) \\ (x + 2)(x + 5)

x=-2 and x=-5

Now

Sum of zeroes=-b/a

-5+(-2)=-7/1

-7=-7

Product of zeroes=c/a

-5×-2=10/1

10=10

Hence Proved

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