find the zeros of polynomial x^3+2x^2-9x-18
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Hyy Dude ♡
➨Zero of polynomial = x³ + 2x² - 9x-18 :
Factor by grouping and using the difference of squares identity to find zeros:
X = 3, x = - 3, = - 2
Explanation:
The difference of squares identity can be written.
a ² - b² = ( a-b) (a+b)
We use this with a = x and b = 3, below, but first factor by grouping:
- F(x) = x³ + 2x² - 9x - 18
- (x³ + 2x²) - ( 9x+18)
- x² ( x+2) - (9x+2 )
- (x² - 9) ( x + 2)
- (x² - 3²) ( x+2)
- ( x-3) ( x + 3) ( x+ 2)
➜Hence zeros :
x= 3,x = - 3 and x = - 2
Hope it's helps you ✨
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