Find the zeros of polynomial x³-2x²-5x.
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Step-by-step explanation:
y(x)= x^3+2x^2–5x+2,
At the point of interception with x axis, y=0,
We find that substituting x=1, y(1)=0,
Therefore x= 1 is one of the x intercepts.
Factoring out the root at x=1, we get y(x)=(x-1)(x^2+3x-2)
The roots of the quadratic equation x^2+3x-2=0 , being real , provide two other x intercepts
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Answer:
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