Question

Find the zeros of polynomial xcube+3xsquare-x-3

Answer 1

Answer:

x= -3 & x= 1

Step-by-step explanation:

= x^3+3x^2-x-3

= x^2(x+3)-1(x+3)

= (x+3)(x^2-1)

now ,

x+3=0

x=0-3

x= -3

and,

x^2-1=0

x^2=0+1

x^2= 1

x=√1

x=1