Question

Find the zeros of polynomial xsq - 3x - 38

Answer 1

Correct Question: Find the zeroes of polynomial x² - 3x - 18

Solution:

p(x) = x² - 3x - 18

Splitting the middle term,

=> x² - 6x + 3x - 18

=> x( x - 6) + 3 ( x - 6)

=> (x - 6)( x + 3)

x - 6 = 0 | x + 3 = 0

x = 6 | x = - 3

Therefore, Zeroes of the polynomial are 6 and -3