Math, asked by vineet44261, 5 months ago

find the zeros of polynomials
 {x }^{2}  - 3x - 1

Answers

Answered by nalanagulajagadeesh
1

Answer:

roots of polynomial is given by,

[-b±√(b^2-4ac)]/2a,

= [-(-3)±√(3^2-4*1*(-1))]/2*1,

= [3±√13]/2 are the roots of the polynomial.

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