find the zeros of polynomials
![{x }^{2} - 3x - 1 {x }^{2} - 3x - 1](https://tex.z-dn.net/?f=+%7Bx+%7D%5E%7B2%7D++-+3x+-+1)
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Answer:
roots of polynomial is given by,
[-b±√(b^2-4ac)]/2a,
= [-(-3)±√(3^2-4*1*(-1))]/2*1,
= [3±√13]/2 are the roots of the polynomial.
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