Question

Find the zeros of polynomical x2-5x-14 and verify the relationship between the zeros and coefficient

Answer 1

Answer:

x²-5x-14=0

x²-7x+2x-14=0

x(x-7)+2(x-7)=0

x = 7, -2

$\alpha = 7 \: and \: \beta = - 2 \\ \alpha + \beta = - b \div a \\ 7 - 2 = - ( - 5) \div 1 \\ 5 = 5 \\ \alpha \beta = c \div a \\ 7 \times - 2 = - 14 \div 1 \\ - 14 = - 14$